x-(x^2+9x+20)+3=0

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Solution for x-(x^2+9x+20)+3=0 equation: 



x-(x^2+9x+20)+3=0

We get rid of parentheses

-x^2+x-9x-20+3=0

We add all the numbers together, and all the variables

-1x^2-8x-17=0

a = -1; b = -8; c = -17;
Δ = b2-4ac
Δ = -82-4·(-1)·(-17)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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